62x^2-96=0

Solution for 62x^2-96=0 equation:

62x^2-96=0

a = 62; b = 0; c = -96;
Δ = b2-4ac
Δ = 02-4·62·(-96)
Δ = 23808
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{23808}=\sqrt{256*93}=\sqrt{256}*\sqrt{93}=16\sqrt{93}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{93}}{2*62}=\frac{0-16\sqrt{93}}{124}
=-\frac{16\sqrt{93}}{124}
=-\frac{4\sqrt{93}}{31}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{93}}{2*62}=\frac{0+16\sqrt{93}}{124}
=\frac{16\sqrt{93}}{124}
=\frac{4\sqrt{93}}{31}
$